Answer:
The three points on the plane found are: (5, 3); (1, 5); and (-3. 7)
Step-by-step explanation:
We can find three points that satisfy the equation by solving for example for the variable "x", and using different possible "y" values to find which "x" produces an equality (and therefore belongs to the line):
[tex]x+2y=11\\x=11-2y[/tex]
So now, we can try three different values for "y" (like 3, 5, and 7)
They give the following x-values:
[tex]x=11-2y\\x=11-2 \,(3)\\x=11-6=5[/tex] [tex]x=11-2y\\x=11-2 \,(5)\\x=11-10=1[/tex] [tex]x=11-2y\\x=11-2 \,(7)\\x=11-14=-3[/tex]
So we have the following three points: (5, 3); (1, 5); and (-3. 7)
which we can plot, and join with a line as shown in the attached image.
