Answer:
[tex]n_{HCl|=1.25\times 10^{-2}\ moles[/tex]
Explanation:
We know that , the reaction between NaOH and HCl is given as
[tex]HCL+NaOH\rightarrow NaCl+H_2O[/tex]
Form the above reaction we can say that
Number of moles of HCl =Number of moles of NaOH
[tex]n_{HCl} =n_{NaOH}[/tex]
Therefore
[tex]n_{HCl}=\frac{0.25\times 50}{1000}\ moles[/tex]
[tex]n_{HCl|=12.5\times 10^{-3}\ moles[/tex]
[tex]n_{HCl|=1.25\times 10^{-2}\ moles[/tex]
Therefore the numbers of moles needed of HCl wil be [tex]1.25\times 10^{-2}\ moles[/tex]
The number of mole of HCl needed to completely react with 50.0 mL of 0.250 M NaOH solution is 1.25×10¯² mole
We'll begin by calculating the number of mole of NaOH in the solution.
Volume = 50 mL = 50 / 1000 = 0.05 L
Molarity of NaOH = 0.250 M
Mole = Molarity x Volume
Mole of NaOH = 0.250 × 0.05
Finally, we shall determine the number of mole of HCl required to react with 1.25×10¯² mole of NaOH. This can be obtained as follow:
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
1 mole of NaOH reacted with 1 mole of HCl.
Therefore,
1.25×10¯² mole of NaOH will also react with 1.25×10¯² mole of HCl
Thus, the number of mole of HCl needed for the reaction is 1.25×10¯² mole
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