Answer:
The answer is 2988 bits per seconds
Explanation:
Solution
Given that:
Bandwidth (B) = 300Hz
Signal to noise ratio (SNR) = 30dB
Now let C = channel capacity
Using Deubel formula we have the following:
SNR db = 10* log (SNR)
30 =10* log (SNR)
So,
SNR =log^⁻1 (3)
SNR = (10)^3
SNR = 1000
Thus SNR =1000
Now
Applying the Shannon's equation
C = B * log₂ ( 1 + SNR)
C = 300 * log₂ ( 1 + 1000)
C = 300 * log₂ (1001)
C = 300 * 9.96
C =2988
Hence the capacity of the channel for teleprinter channel is 2988 bits per second.
