As energy is conserve:
[tex]Epi+Ekl=Epf+Ekf[/tex]
i - initial
f - final
Beginning object at rest, [tex]Eki=0[/tex]. Object on the lowest position, hence [tex]Epf=0[/tex].
Therefore:
[tex]Epi=Epf[/tex]
[tex]M.g.h.=\frac{1}{2} (v^{2} )[/tex]
Assume no Mass changed:
[tex]g.h.=\frac{1}{2}( v^{2} )[/tex]
V is at bottom and assuming that [tex]g=\frac{10m}{s^2}[/tex]:
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2(10)(80)}[/tex]
[tex]v=\sqrt{1,600}[/tex]
[tex]v=40[/tex]
The velocity is [tex]40m/s[/tex]