Answer:
y = [tex]-\frac{1}{4}[/tex]x + 6 or y = [tex]-\frac{1}{4}[/tex]x - 0.375
Step-by-step explanation:
For 2 lines to be perpendicular, their slopes must be negative reciprocals. In order to find the perpendicular of y - 4x - 6 = 0:
SLOPE INTERCEPT FORM: y = 4x + 6
SLOPE OF LINE A: m=4
SLOPE OF LINE B (the one you are looking for): m=[tex]-\frac{1}{4}[/tex]
Since I don't know if you meant that they intercept on the x or y axis I will do both.
y-axis
y-6=[tex]-\frac{1}{4}[/tex](x-0)
y = [tex]-\frac{1}{4}[/tex]x+6
x-axis
y-0=[tex]-\frac{1}{4}[/tex](x-1.5)
y=[tex]-\frac{1}{4}[/tex]x-0.375
