Answer:
[tex]x=6\,\,units\,,\,EF=34 \,\,units\,,\,FG=25\,\,units[/tex]
Step-by-step explanation:
Given: [tex]EG =59 \,\,units[/tex]
To find: [tex]x,EF,FG[/tex]
Solution:
From the image, [tex]EG=EF+FG[/tex]
Put [tex]EF=8x-14\,,\,FG=4x+1\,,\,EG=59[/tex]
[tex]8x-14+4x+1=59\\12x-13=59\\12x=59+13\\\\12x=72\\x=\frac{72}{12}=6[/tex]
[tex]EF=8x-14=8(6)-14=48-14=34\\FG=4x+1=4(6)+1=24+1=25[/tex]
Therefore,
[tex]x=6\,\,units\,,\,EF=34 \,\,units\,,\,FG=25\,\,units[/tex]
