Answer:
The molarity of the final solutions if these two solutions are mixed is 27.14 [tex]\frac{moles}{L}[/tex]
Explanation:
Yo know:
Molarity being the number of moles of solute per liter of solution, expressed by:
[tex]Molarity (M)= \frac{number of moles}{volume}[/tex]
You can determine the number of moles that are mixed from each solution as:
Number of moles= Molarity*Volume
So, being 1 L=1000 mL, for each solution you get:
When mixing both solutions, it is obtained that the volume is the sum of both solutions:
Total volume= volume solution-1 + volume solution-2
and the number of total moles will be the sum of the moles of solution-1 and solution-2:
Total moles= moles of solution-1 + moles of solution-2
So the molarity of the final solution is:
[tex]Molarity (M)= \frac{moles of solution 1 + moles of solution 2}{Volume solution 1 + Volume solution 2}[/tex]
In this case, you have:
Replacing:
[tex]Molarity (M)=\frac{10 moles + 9 moles}{0.400 L + 0.300 L}[/tex]
Solving:
[tex]Molarity (M)=\frac{19 moles}{0.700 L}[/tex]
Molarity= 27.14 [tex]\frac{moles}{L}[/tex]
The molarity of the final solutions if these two solutions are mixed is 27.14 [tex]\frac{moles}{L}[/tex]
