Find the arc length parameter along the curve from the point where t=0 by evaluating the integral s= V(T) dt. Then find the length of the indicated portion of the curve.
r(t) = (4 + 5t)i + (8 + 2t)j + (2 - 7t)k, -1sts

Respuesta :

Answer:

L = 8.831 t

Step-by-step explanation:

You have the following vector:

[tex]r(t)=(4+5t,8+2t,2-7t)[/tex]

To find the arc length you use the following formula:

[tex]L=\int_a^b \sqrt{(\frac{dx}{dt})^2+(\frac{dy}{dt})^2+(\frac{dz}{dt})^2}dt[/tex]   (1)

where dx/dt, dy/dt and dz/dt are the components of the vector dr/dt.

Then, you calculate dr/dt:

[tex]\frac{d\vec{r}}{dt}=(5,2,-7)[/tex]

Next you replace in the integral of the equation (1):

[tex]L=\int_o^t\sqrt{(5)^2+(2)^2+(-7)^2}=8.831t|_o^t=8.831t[/tex]

hence, the arc length is L = 8.831t