Which situation can be represented by this inequality? 50−3.50x>100−6x Select one: A. Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have less money on his gift card than David? B. Daniel has a $50 Dunkin Donuts™ gift card and spends $6 a day. David has a $100 gift card and spends $3.50 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? C.Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? D. Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have the same amount of money on his gift card as David?

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berno berno · Answer 1 · 2020-06-20T15:17:21+02:00

Answer:

Option C is correct

Step-by-step explanation:

Given: inequality is [tex]50-3.50x>100-6x[/tex]

To find: situation that can be represented by the given inequality

Solution:

Cost of Dunkin Donuts gift card with Daniel = $50

Amount spent by Daniel per day = $3.50

Cost of Dunkin Donuts gift card with David = $100

Amount spent by David per day = $6

Amount left with Daniel after x days = [tex]\$(50-3.50x)[/tex]

Amount left with David after x days = [tex]\$(100-6x)[/tex]

According to question,

Amount left with Daniel after x days > Amount left with David after x days

[tex]50-3.50x>100-6x[/tex]

So, he inequality that satisfies the situation is [tex]50-3.50x>100-6x[/tex]

Option C is correct