FH is the altitude to the hypotenuse EG. what is the length of FH. Really need some help with this!
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Answer:
Option A is correct
Step-by-step explanation:
Given: FH is the altitude to the hypotenuse EG
To find: length of FH
Solution:
According to Pythagoras theorem, square of hypotenuse is equal to sum of squares of other two sides.
In [tex]\Delta EHF[/tex],
[tex]\angle EHF=90^{\circ}[/tex]
So,
[tex]EF^2=EH^2+FH^2[/tex]
Put EH = 6 units and EF = 7 units
[tex]7^2=6^2+FH^2\\49=36+FH^2\\49-36=FH^2\\13=FH^2[/tex]
Option A is correct
Take square root on both sides
[tex]FH=\sqrt{13}=3.606\,\,units[/tex]