Answer:
Solution is not correct.
Step-by-step explanation:
Given question is incomplete; Here is the complete question.
Is the solution shown in the attachment correct ?
9x + 2 = 8x² + 6x
We have to solve this equation with the help of quadratic formula,
-8x² + 9x + 2 = 6x
-8x² + 9x - 6x + 2 = 0
-8x² + 3x + 2 = 0
Quadratic formula of a standard quadratic equation (ax² + bx + c = 0) is,
x = [tex]\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}[/tex]
By comparing our equation with the standard quadratic equation,
a = -8
b = 3
c = 2
By substituting the values of a, b and c in the quadratic formula,
x = [tex]\frac{-3\pm\sqrt{(3)^{2}-4(-8)(2)}}{2(-8)}[/tex]
x = [tex]\frac{-3\pm\sqrt{9+64} }{-16}[/tex]
x = [tex]\frac{9\pm\sqrt{73}}{16}[/tex]
Therefore, the given solution is not correct.
Answer:
Sample Response/Explanation
Step-by-step explanation:
No. The correct values of a, b, and c were substituted in, but the formula was simplified wrong. The 64 should be added so the radicand is 73. There should be 2 real roots.
