If the pattern below follows the rule "Starting with five, every consecutive line has a number one more than the previous line," how many marbles must be in the seventh line?

Step-by-step explanation: all you have to do is start from add 1 each time you add a new line. You could do this using your fingers. Raise a finger for each line and count. Start at 5 for your first finger, and continue adding 1. Once you reach 7 fingers, you’ll have reached the number 11. This is the amount of marbles you have. You could also simply do 6+5, because you are adding 6 lines so you’ll have 6 more marbles then in the first line.

RajarshiG RajarshiG · Answer 2 · 2022-07-09T11:22:15+02:00

As per arithmetic progression, the number of marbles in the seventh line is 11.

What is an arithmetic progression?

"Arithmetic Progression is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value."

The first line has (a) 5 marbles.

Every consecutive line has a number one more than the previous line.

Therefore the common difference between two consecutive lines (d) is 1.

Therefore, as per arithmetic progression the seventh line [tex](n = 7)[/tex] has marbles

[tex]= a+(n-1)d\\= 5+(7-1)1\\= 5+6\\= 11[/tex]

Learn more about an arithmetic progression here: https://brainly.com/question/24873057

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