Answer:
43x + 5y - 4z = 12
Step-by-step explanation:
x+3y−z=64x−2y+2z=−106x+z=−12
The solution is given if you group all x y and z together. The 'problem' is you have three equal signs...
If you want, you can split it into three steps.
1. Group the two first equations.
x+3y−z=64x−2y+2z
x+3y−z=64x−2y+2z
x - 64x + 3y + 2y −z -2z
-63x + 5y - 3z
2. Group the last two equations.
−106x+z=−12
−106x+z +12 = 0
3. Now use answer 1. and set it equal to answer 2, and group these equations.
-63x + 5y - 3z = −106x +z + 12
-63x + 106x + 5y - 3z -z = 12
43x + 5y - 4z = 12
And this is the answer we are looking for.
