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Please Help!!! An engine takes 3,000 J from a hot reservoir and expels 2,400 J to a cold reservoir. What is the thermal efficiency of the engine? 20% 45% 60% 80%

Respuesta :

Answer:

80%

Explanation:

Thermal efficiency is a measure of the extent to which a heat engine is able to convert to other form. It is measure in percentage.

Thermal efficiency = [tex]\frac{E_{out} }{E_{in} }[/tex] × 100%

Where [tex]E_{in}[/tex] is the input energy and [tex]E_{out}[/tex] is the output energy.

Given that: [tex]E_{in}[/tex] = 2400 J and  [tex]E_{out}[/tex] = 3000 J, therefore:

Thermal efficiency = [tex]\frac{2400}{3000}[/tex] × 100%

                               = 80%

The thermal efficiency of the engine is 80%.

The thermal efficiency of the engine is 80%

The parameters given in the question are;

Input= 3000J

Output= 2,400J

Output/Input × 100

= 2400/3000 × 100

= 0.8 × 100

= 80%

The thermal efficiency of the engine is 80%

Please see the link below for more information

https://brainly.com/question/23719522?referrer=searchResults