1. Write a program in C++ that can convert a given integer value
into words. Assume the largest integer value to be 999 billion
For an input of say 1108 your out should be ONE THOUSAND
ONE HUNDRED AND EIGHT​

Respuesta :

Answer:

Hope this works

#include <iostream>

   #include <string>

   #include <vector>

   using namespace std;

   string digitName(int digit);

   string teenName(int number);

   string tensName(int number);

   string intName(int number);

   vector<string> ones {"","one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};

   vector<string> teens {"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen","sixteen", "seventeen", "eighteen", "nineteen"};

   vector<string> tens {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};

   string nameForNumber (long number) {

       if (number < 10) {

           return ones[number];

       } else if (number < 20) {

           return teens [number - 10];

       } else if (number < 100) {

           return tens[number / 10] + ((number % 10 != 0) ? " " + nameForNumber(number % 10) : "");

       } else if (number < 1000) {

           return nameForNumber(number / 100) + " hundred" + ((number % 100 != 0) ? " " + nameForNumber(number % 100) : "");

       } else if (number < 1000000) {

           return nameForNumber(number / 1000) + " thousand" + ((number % 1000 != 0) ? " " + nameForNumber(number % 1000) : "");

       } else if (number < 1000000000) {

           return nameForNumber(number / 1000000) + " million" + ((number % 1000000 != 0) ? " " + nameForNumber(number % 1000000) : "");

       } else if (number < 999000000001) {

           return nameForNumber(number / 1000000000) + " billion" + ((number % 1000000000 != 0) ? " " + nameForNumber(number % 1000000000) : "");

       }

       return "error";

   }

   int main()

   {

       long input;

       do

       {

           cout << "Please enter a positive integer: ";    

           cin >> input;

           cout << "\n" << nameForNumber(input) << endl;

           cout << "\n\n" << endl;

       }while (input > 0);

       return 0;

   }