Answer:
The P-value for this test is P=0.017.
Step-by-step explanation:
We have the null and alternative hypothesis:
[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0[/tex]
where the subindex 1 refers to the males proportion and the subindex 2 refers to the female proportion.
The difference in proportions is 0.172018 and the test statistic is z=2.11825.
As this is a right-tailed test, the P-value can be calculated using the standard normal distribution table as:
[tex]\text{P-value}=P(z>2.11825)=0.017[/tex]