contestada

2H is a loosely bound isotope of hydrogen, called deuterium or heavy hydrogen. It is stable but relatively rare — it form only 0.015% of natural hydrogen. Note that deuterium has Z = N, which should tend to make it more tightly bound, but both are odd numbers.

Required:
Calculate BE/A, the binding energy per nucleon, for 2H in megaelecton volts per nucleon

Respuesta :

whitneytr12

Answer:

0.88 MeV/nucleon

Explanation:

The binding energy (B) per nucleon of deuterium can be calculated using the following equation:

[tex] B = \frac{Zm_{p} + Nm_{n} - M}{A}*931.49 MeV/u [/tex]

Where:

Z: is the number of protons = 1

N: is the number of neutrons = 1

[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u

[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u

M: is the nucleu's mass = 2.01410

A = Z + N = 1 + 1 = 2    

Now, the binding energy per nucleon for ²H is:

[tex]B = \frac{Zm_{p} + Nm_{n} - M}{A}*931.49 MeV/u = \frac{1*1.00730 + 1*1.00869 - 2.01410}{2}*931.49 MeV/u = 9.45 \cdot 10^{-4} u*931.49 MeV/u = 0.88 MeV/nucleon[/tex]

Therefore, the binding energy per nucleon for ²H is 0.88 MeV/nucleon.

I hope it helps you!

Otras preguntas