Answer:
9.53g
Explanation:
Given the following :
Density = 1.065g/mL
Volume of solution = 25.0mL
% of acetic acid =58%
Molar mass of CH3COOH = 60.05g/mol
Molar mass of Ca(OH)2 = 74.093g/mol
Reaction:
2CH3COOH + Ca(OH)2 ----> Ca(CH3Co2)2 +2H2O
Volume of solution × density × % of CH3COOH × (mole per molar mass CH3COOH) × (mole of Ca(OH)2 per mole of CH3COOH) × (molar mass of Ca(OH)2 per mole of Ca(OH)2)
25mL × (1.065/1) × (58/100) × (1 / 60.05) × (1 / 2) × (74.093 / 1)
25 × 1.065 × 0.58 × 0.0166527 × 0.5 × 74.093
= 9.526g
