The angle of deperession of aPt A, as measured form the top of
abuilding 30m tall is 450, how far is A from the basc of the
building?
A. 97m B. 30m C. 45m D. 32m


Respuesta :

Answer:B

Step-by-step explanation:

Given

Height of building [tex]h=30\ m[/tex]

Angle of depression [tex]\theta =45^{\circ}[/tex]

Suppose distance of Point A from base of building be  [tex]x[/tex]

From diagram we can write

[tex]\Rightarrow \tan \theta =\dfrac{h}{x}[/tex]

[tex]\Rightarrow \tan (45^{\circ})=\dfrac{30}{x}[/tex]

[tex]\Rightarrow 1=\dfrac{30}{x}[/tex]

[tex]\Rightarrow x=30\ m[/tex]

So, point A is [tex]30\ m[/tex] from base of building

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