Answer:
The [H⁺] for this soluton is 2*10⁻³ M
Explanation:
pH, short for Hydrogen Potential and pOH, or OH potential, are parameters used to measure the degree of acidity or alkalinity of substances.
The values that compose them vary from 0 to 14 and the pH value can be directly related to that of pOH by means of:
pH + pOH= 14
In this case, pOH=11.30, so
pH + 11.30= 14
Solving:
pH= 14 - 11.30
pH= 2.7
Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O):
´pH= - log [H⁺] = -log [H₃O]
Being pH=2.7:
2.7= - log [H⁺]
[H⁺]= 10⁻² ⁷
[H⁺]=1.995*10⁻³ M≅ 2*10⁻³ M
The [H⁺] for this soluton is 2*10⁻³ M
The pH of the NaOH solution has been 2.7. The hydrogen ion concentration of the NaOH solution has been 1.9 [tex]\rm \bold{\times\;10^-^3}[/tex] M.
The pH of the solution has been used for the determination of the Hydrogen ion concentration in the solution. The higher the hydrogen ion concentration, the pH will tend to be more towards the lower side.
The pOH has been the hydroxide ion concentration in the solution, The higher the hydroxide ion concentration, the more pH will move towards the higher range.
The sum of pH and pOH has been the constant quantity.
pH + pOH = 14
The given NaOH solution has pOH 11.30. The pH of the solution will be:
pH + 11.30 = 14
pH = 14 - 11.30
pH = 2.7.
The pH of the NaOH solution has been 2.7.
pH can be defined as the negative log of the hydrogen ion concentration.
pH = -log [[tex]\rm H^+[/tex]]
2.7 = log [[tex]\rm H^+[/tex]]
[[tex]\rm H^+[/tex]] = [tex]\rm 10^-^2^.^7[/tex]
[[tex]\rm H^+[/tex]] = 1.9 [tex]\rm \bold{\times\;10^-^3}[/tex] M
The hydrogen ion concentration of the NaOH solution has been 1.9 [tex]\rm \bold{\times\;10^-^3}[/tex] M.
For more information about the pH, refer to the link:
https://brainly.com/question/22299206
