[tex]\frac{6-3(\sqrt[3]{6})}{\sqrt[3]{9}}[/tex][tex]\frac{6-3(\sqrt[3]{6})}{\sqrt[3]{9}}[/tex][tex]2(\sqrt[3]{3})-\sqrt[3]{18}[/tex] option (A) is Correct.
What is Rationalization?
- It is a process that finds application in elementary algebra, where it is used to eliminate the irrational number in the denominator.
How to Solve the problem ?
The problem can be solved by following steps.
The expression given is [tex]\frac{6-3(\sqrt[3]{6})}{\sqrt[3]{9}}[/tex]
So , The first step we will do is Rationalize the figure
= [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt{9^2} }}{\sqrt[3]{9}*\sqrt[3]{9} }[/tex]
The product of radicals with the same index equals the radical of the product:[tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt{9^2} }} {\sqrt[3]{9*9^2} }[/tex]
Simplify using exponent with same base
[tex]a^{n}*a^{m} = a^{a+m}[/tex]
= [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt{9^2} }} {\sqrt[3]{9^1+^2} }[/tex]
Calculate the sum or difference: [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt{9^2} }} {\sqrt[3]{9^3} }[/tex]
Simplify the radical expression: [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt{9^2} }} {{9} }[/tex]
Calculate the power : [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt[3]{3} }} {{9} }[/tex]
Cross out the common factor: [tex]\frac{6-3(\sqrt[3]{6})*3 {\sqrt[3]{3} }} {{3} }[/tex]
Factor Greatest Common Factors : [tex]\frac{3*2\sqrt[3]{3}-\sqrt[3]{18} }{3}[/tex][tex]3*2\sqrt[3]{3}-\sqrt[3]{18}}[/tex]
Reduce the fraction : [tex]2\sqrt[3]{3}-\sqrt[3]{18}}[/tex]
Hence the First option is correct
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