Respuesta :
Answer:
Copper ii nitrate is the limiting reagent
Explanation:
The first thing to write here is the equation of reaction;
Fe + Cu(NO3)2 ——> Fe(NO3)2 + Cu
When we talk of limiting reagent, we mean the reactant that is totally consumed upon the completion of the chemical reaction
To get the limiting reagent, we can know this by calculating the mass of a specific product formed from each of the masses of the reactants
Now, we can use the amount of copper solid deposited by each of the reactants to know the limiting reagent here.
Since the mole ratio in all cases is 1 to 1, this will be easy
For the iron, the number of moles reacted is mass of iron/ atomic mass of iron
That would be 119.5/56 = 2.134 moles
Now since the mole ratio is 1 to 1, 2.134 moles of copper will be formed
Thus, the mass of copper produced from the iron will be number of moles * atomic mass of copper = 2.134 * 64 = 136.57g
Now from the nitrate, the number of moles is
mass mixed/ molar mass of copper nitrate
molar mass of copper nitrate is 188g/mol
number of moles is thus 279.5/188 = 1.487 moles
Since the mole ratio is 1 to 1, it means that the number of moles of copper produced too is 1.487 moles
The mass of copper produced from this is number of moles of copper * atomic mass of copper
That will be 1.487 * 64 = 95.15g
Now, since the copper nitrate produces less amount of copper solid, it is the the reagent to be consumed first and thus it is our limiting reagent
