Answer:
It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.
Explanation:
[tex]d=v_ot+\dfrac{1}{2}at^2[/tex]
Since the intial velocity of a dropped object is 0, we can make this the equation:
[tex]d=\dfrac{1}{2}at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900[/tex]
[tex]t=30\text{ seconds}[/tex]
The final velocity can be calculated with the formula:
[tex]v_f=v_o+at[/tex]
Once again, since there is no initial velocity:
[tex]v_f=at \\\\v_f=(9.8)(30)=294m/s[/tex]
Since the intial velocity is 0, the average vertical velocity is 294/2=147 m/s.
Hope this helps!
