Answer:
[tex]\dfrac{\pi}{4},\dfrac{3\pi}{4}[/tex]
Step-by-step explanation:
[tex]2\sin^2(\theta)=1[/tex]
Divide both sides by 2:
[tex]\sin^2(\theta)=\dfrac{1}{2}[/tex]
Take the square root of both sides:
[tex]\sin(\theta)=\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}[/tex]
The only two places on the unit circle where the y value of the point is [tex]\dfrac{\sqrt{2}}{2}[/tex] are at:
[tex]\dfrac{\pi}{4},\dfrac{3\pi}{4}[/tex]
Hope this helps!
