Respuesta :

Answer:

[tex]b=8\sqrt{3}, c=16[/tex]

Step-by-step explanation:

Since the ratios of sides in a 30-60-90 triangle are [tex]1:\sqrt{3}:2[/tex], b must be [tex]8\sqrt{3}[/tex] and c must be 16. Hope this helps!

Answer:

b = 8√3

c = 16

Step-by-step explanation:

We cannot yet use the Pythagorean theorem because we only have one leg of the triangle

However, we can use trig identities to solve for the missing legs

I'll solve for b first so we can use the Pythagorean theorem after to find c

  • We can use any of the trig identities to solve for b, but I will use the tangent identity since it involves the leg we were given
  • [tex]tan(\alpha )=\frac{opposite}{adjacent}[/tex]
  • Then solving for "opposite" which is our "b" will give us opposite = (adjacent)(tan(Ф))
  • Plugging in our known values we get b = (8)(tan(60°)) = (8)(√3) = 8√3

Now that we have two legs of the triangle we can use the Pythagorean theorem to solve for the remaining leg, c.

  • a² + b² = c² → [tex]c=\sqrt{a^2+b^2}[/tex]
  • Plugging in our two legs of the triangle we get [tex]c=\sqrt{(8)^2+(8\sqrt{3} )^2}=\sqrt{64+192}=\sqrt{256}[/tex]
  • c = 16