Answer:
[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
[tex]P[/tex] (number > 2)
The values we can roll to satisfy the condition that the roll be greater than 2 are: 3, 4, 5, 6 - and so there are 4 values we can roll.
The number of values we can get on a standard number cube is 1,2, 3, 4, 5, 6
- and so 6 values.
Which gives us
[tex]P[/tex] (number > 2)=
[tex]\frac{4}{6} =\frac{2}{3}[/tex]
Hope this helps,
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