Answer:
TP: 13
Step-by-step explanation:
A=((b1+b2)/2)*h
100=((8+32)/2)*h
100=(40/2)*h
100=20h
h=5
A=8*5+((32-8)/2)*0.5*5*2
100=40+(24/2)*5
60=12*5
thus, point E is is 12 away from T
Triangle TPE:
the catets are TE:12 and PE:5
Lets use the Pythagorean theorem:
a^2+b^2=c^2
12^2+5^2=c^2
144+25=c^2
169=c^2
c=(+/-)13
since distance can only be positive, the answer is:
segment TP has the length of 13 units
