Answer: [tex]\bold{x=8\pm \sqrt{373}}[/tex]
Step-by-step explanation:
x² + 306 = 16x - 3
Subtract 16x and 306 from both sides:
x² - 16x = -309
Add (-16/2)² to both sides to create a perfect square on the left:
[tex]x^2 - 16x + \bigg(\dfrac{-16}{2}\bigg)^2=309+\bigg(\dfrac{-16}{2}\bigg)^2\\\\\\\text{Simplify:}\\(x-8)^2=373\\\\\\\text{Square root both sides:}\\x - 8 = \pm\sqrt{373}\\\\\\\text{Add 8 to both sides:}\\x=8\pm \sqrt{373}[/tex]
