The cone in Fig. 15.29 is exactly half full of water
by volume. How deep is the water in the cone?
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Answer:
The water is 8 cm deep.
Step-by-step explanation:
In order to solve this problem we first need to find the total volume of the cone, this is done by using the following formula:
[tex]V = \frac{\pi*r^2*h}{3}\\\\V = \frac{\pi*(6)^2*16}{3}\\\\V = \frac{576*\pi}{3}\\\\V = 192*\pi[/tex]
The total volume of the cone is 192*pi cm³, if it is half full then the volume of the water is half of that, which would be 96*pi cm³, we can apply this value to the same formula in order to find the height of the water:
[tex]96\pi = \frac{\pi*(6)^2*h}{3}\\\\\pi*36*h = 288\pi\\h = \frac{288}{36}\\h = 8 \text{ cm}[/tex]
The water is 8 cm deep.