Factor the trinomial completely.
2x^4 -20x^2+ 32
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Answer:
2(x² - 2)(x² - 8)
Step-by-step explanation:
Given
2[tex]x^{4}[/tex] - 20x² + 32 ← factor out 2 from each term
= 2([tex]x^{4}[/tex] - 10x² + 32)
let u = x², then
[tex]x^{4}[/tex] - 10x² + 32 = u² - 10u + 32 = (u - 2)(u - 8)
change u back to x²
[tex]x^{4}[/tex] - 10x² + 32 = (x² - 2)(x² - 8) and
2[tex]x^{4}[/tex] - 20x² + 32 = 2(x² - 2)(x² - 8) ← in factored form