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A stone is thrown in the upwards direction at the velocity of 4 m/s. It attains a certain height and then it falls back. During its motion, it experienced an acceleration of 10 m/s2 in the downward direction. What is the maximum height it attained before falling back?

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Answer: 0.8 m

Explanation:

Velocity of throw = 4m/s

Maximum Height attained(h) =?

Downward acceleration experienced = 10m/s^2

Using the relation:

v^2 = u^2 + 2aS

v = final Velocity = 0 (at maximum height)

u = Initial Velocity = 4

a = g downward acceleration = - 10

0 = 4^2 + 2(-10)(S)

0 = 16 - 20S

20S = 16

S = 16 / 20

S = 0.8m

Maximum Height attained = 0.8m