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An ordinary (falr) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a dle is rolled twice in succession
and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events.
Event A: The sum is greater than 5.
Event B: The sum is an even number.
Write your answers as exact fractions.

Respuesta :

Answer to A:

16.67%

Explanation to A:

If we need a number greater than five, the only number left is six, meaning there is [tex]\frac{1}{6}[/tex]

[tex]\frac{1}{6} = 0.166666666[/tex]

We can make it a percent by moving the decimal two places to the right and rounding to the thousandths place (two numbers). This would make our final answer 16.67%

Answer to B:

50%

Explanation to B:

There are three even numbers: 2, 4, and 6. This means we have a [tex]\frac{3}{6}[/tex] chance to land on one.

[tex]\frac{3}{6} = 0.5[/tex]

0.5 = 50%