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A dance club hires two different DJ’s to
play music on a Friday night. The hip hop
DJ charges $100 per hour, while the rap DJ
charges $50 per hour. The club can spend
a maximum of $800, and they want both
types of music played.
Let “x” represent the number of hours of
hip hop and let “y” represent the number
of hours of rap.

Respuesta :

CHERLYNnotCHERRY

Answer:

The expression is 100x + 50y ≤ 800.

Step-by-step explanation:

The hip hop DJ charge for $100 per hour. Let x be number of hours of hip hop :

[tex]hip \: hop = 100 \times x[/tex]

[tex]hip \: hop = 100x[/tex]

For rap DJ, the charge is $50 per hour. Let y be the number of hours of rap :

[tex]rap = 50 \times y[/tex]

[tex]rap = 50y[/tex]

Given that both DJs spend a maximum of $800. So the final expression is :

[tex]100x + 50y \leqslant 800[/tex]

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