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A biker passes a lamppost at the crest of a hill at +4.5 m/s. She accelerates down the hill at a
constant rate of +0.40 m/s² for 12 s. How far does she move down the hill during this time?

Respuesta :

SvetkaChem

Answer:

82.8 m

Explanation:

[tex]d = v_{0}t + \frac{at^_2}{2}\\\\d = 4.5 m/s*12s +\frac{0.40 m/s^{2}*(12s)^{2}}{2} = 82.8 m[/tex]

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