if one 30 60 90 triangle has a short leg 8 inches long,and another has a short leg of 24 inches long, find the area of each triangle, and compare their sizes

Respuesta :

Answer:

The triangle with a short leg= to 24 inches is  times larger than the one with a short side equalling 8 in

Step-by-step explanation:

Given that the short leg is equal to 8, the longer leg is equal to 8[tex]\sqrt{3\\[/tex] . The area of a triangle is equal to 1/2bh. 1/2× 8[tex]\sqrt{3\\[/tex]×8 = 55.43 approx.

Given that the short leg is equal to 24, the longer leg is equal to 24[tex]\sqrt{3\\[/tex] . The area of a triangle is equal to 1/2bh. 1/2 × 24[tex]\sqrt{3\\[/tex] ×24 = 498.83 approx.

498.83/55.43= about 9

The second triangle is approximately 9 times the size of the first.