Answer:
The acceleration at lowest point is 19.62 m/s^2
Explanation:
Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.
Lets Assume
Constant of string is K
By using the conservation of energy we will have the following equation
1/2 x 80^2 x K = m x 9.81 x 120
3200 K = 1177.2 m
K = 1177.2 m / 3200
K = 0.368 m
At the lowest point we will have
a = ( K x X - m x g ) / m
a = ( 0.368 m x 80 - m x 9.81 ) / m
a = 19.62 m / s^2
So, the acceleration at lowest point is 19.62 m/s^2
The acceleration at lowest point is [tex]\bold { 19.62\ m / s^2}[/tex], when someone momentarily at rest.
Fom the conservation of energy equation,
[tex]\bold {\dfrac 12 \times 80^2 \times K = m \times 9.81 \times 120}\\\\\bold {3200 K = 1177.2\times m}\\\\\bold {K = \dfrac {1177.2\times m}{ 3200}}\\\\\bold {K = 0.368 m}[/tex]
At the lowest point
[tex]\bold {a =\dfrac { K\times X - m \times g ) }{ m}}\\\\\bold {a =\dfrac { 0.368 m \times 80 - m \times 9.81 } m}\\\\\bold {a = 19.62\ m / s^2}[/tex]
Therefore, the acceleration at lowest point is [tex]\bold { 19.62\ m / s^2}[/tex].
To know more about acceleration,
https://brainly.com/question/17059123
