contestada

OA

⊥

OC

start overline, O, A, end overline, \perp, start overline, O, C, end overline

\qquad m \angle AOB = 6x - 12^\circm∠AOB=6x−12

∘

m, angle, A, O, B, equals, 6, x, minus, 12, degrees

\qquad m \angle BOC = 3x + 30^\circm∠BOC=3x+30

∘

m, angle, B, O, C, equals, 3, x, plus, 30, degrees

Find m\angle AOBm∠AOBm, angle, A, O, B:

Respuesta :

Answer:

36°

Step-by-step explanation:

We know that angles BOC and AOB are complementary angles, that is, the sum 90°. Additionally, we know that

[tex]\angle BOC=3x+30[/tex] and [tex]\angle AOB = 6x-12[/tex], which can be expressed as

[tex]3x+30+6x-12=90[/tex]

Let's solve for [tex]x[/tex]

[tex]9x=72\\x=\frac{72}{9}\\ x=8[/tex]

Using this vale, we find the measure of angle AOB

[tex]\angle AOB = 6x-12=6(8)-12 =48-12=36\°[/tex]

Therefore, the answer is 36°.

riosisabella015

Answer:

its 36 degrees i just did it

Step-by-step explanation:

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