Answer:
The Probability is found as:
A) P = 23/36
Step-by-step explanation:
When two dices are rolled, each dice has a total outcomes of 6. The total number of outcomes of both dices is:
[tex]6\cdot6=36\\[/tex]
Find the pair of values (x₁ , x₂) for which sum is 6 or odd number, where x₁ is the number on first dice and x₂ is the number on the second dice.
(1,2),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(3,2),(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,5),(5,1),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)
So Desired number outcomes = 23
So, Probability is given as:
P = Desired number outcomes / Total number of outcomes
P = 23/36
