Answer:
C
Step-by-step explanation:
The picture is a bit blurry, but from what i can see, i'd say C (whichever one has -4 x 3 x 1 under the square root.)
So for this, you need to know the quadratic formula, which is:
[tex]\frac{-b ± \sqrt{b^{2} -4ac} }{2a}[/tex]
*ignore the weird capital A, it keeps coming up when i try to use the ± symbol
They have given you the equation of a quadratic, so the first thing you have to do is rearrange it, so that [tex]x^{2}[/tex] comes first.
So now we have the equation: 3[tex]x^{2}[/tex] - 2x +1
*the quadratic formula uses a, b and c, but they are specific. a is always the coefficient of [tex]x^{2}[/tex] , b is always the coefficient of x and c is always the constant (number without an x)
So, i can find that, in this case:
a = 3 b= -2 c=1
Now substitute each of those values it into the original quadratic equation:
[tex]\frac{-(-2) ± \sqrt{(-2)^{2} -4(3)(1)} }{2(3)}[/tex]
*again, ignore the weird capital A.
That's how you find the answer, which from what i can tell in the picture is C.
Hope that helped : )
