In a random sample of 651 computer scientists who subscribed to a web-based daily news update, it was found that the average salary was $46,816 with a population standard deviation of $12,557. Calculate a 91 percent confidence interval for the mean salary of computer scientists. Choose the closest value from your table.

Respuesta :

Answer:

[tex]46816-1.695\frac{12557}{\sqrt{651}}=45981.81[/tex]    

[tex]46816+ 1.695\frac{12557}{\sqrt{651}}=46650.19[/tex]    

And the confidence interval would be given by: (45981.81; 46650.19)

Step-by-step explanation:

Data given

[tex]\bar X=46816[/tex] represent the sample mean

[tex]\mu[/tex] population mean (variable of interest)

[tex]\sigma=12557[/tex] represent the population standard deviation

n=651 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]   (1)

Since the Confidence is 0.91 or 91%, the significacne is  [tex]\alpha=0.09[/tex] and [tex]\alpha/2 =0.045[/tex], and the critical value is [tex]z_{\alpha/2}=1.695[/tex]

Now we have everything in order to replace into formula (1):

[tex]46816-1.695\frac{12557}{\sqrt{651}}=45981.81[/tex]    

[tex]46816+ 1.695\frac{12557}{\sqrt{651}}=46650.19[/tex]    

And the confidence interval would be given by: (45981.81; 46650.19)