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Bob tosses his basketball onto the ground from his treehouse. He tosses the basketball with an initial downward velocity of 8 feet per second. The equation [tex]h = -16t^2 - 8t + 20[/tex] represents the height h of the basketball after t seconds. How long does the basketball take to hit the ground?

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rococo908

Answer:

0.9 seconds

Step-by-step explanation:

Set t as 0 because it will be on the floor

Simplify by dividing both sides by -4

0 = 4t² + 2t - 5

Use the quadratic formula

t = -2±[tex]\frac{\sqrt{2^2 -4(-20)}}{8}[/tex]

t = ± [tex]\frac{-1 - \sqrt{21} }{4}[/tex]

Because time can only be positive, the correct answer is [tex]\frac{-1 - \sqrt{21} }{4}[/tex],

or ≈ 0.9 seconds

The time taken for basketball take to hit the ground should be 0.9 seconds.

Calculation of the time taken:

Since the basketball with an initial downward velocity of 8 feet per second.

Here we Set t as 0 since it will be on the floor

Also, Simplify by dividing both sides by -4.

0 = 4t² + 2t - 5

Now we have to use the quadratic equation

[tex]t = \pm \frac{-1-\sqrt21}{4}[/tex]

Based on this, we can conclude that The time taken for basketball take to hit the ground should be 0.9 seconds.

Learn more about time here: https://brainly.com/question/13356529

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