The average height of young adult males has a normal distribution with standard deviation of 2.5 inches. You want to estimate the mean height of students at your college or university to within one inch with 90% confidence. How many male students must you measure?

Respuesta :

Answer:

The male students must you measure 'n' = 24

Step-by-step explanation:

Step(i):-

Given Population standard deviation = 2.5 inches

Given the margin of error = 1 inches

Step(ii):-

90% confidence interval of Margin of error is determined by

[tex]M.E = \frac{Z_{\frac{\alpha }{2} } S.D}{\sqrt{n} }[/tex]

[tex]Z_{\frac{0.10}{2} } = Z_{0.05} = 1.96[/tex]

[tex]1 = \frac{1.96 X 2.5}{\sqrt{n} }[/tex]

cross multiplication , we get

√n  =  4.9

squaring on both sides , we get

n = 24.01≅ 24

Final answer:-

The male students must you measure 'n' = 24

The total number of male students is 24 and this can be determined by using the formula of margin of error.

Given :

  • The average height of young adult males has a normal distribution with a standard deviation of 2.5 inches.
  • 90% confidence interval.

The formula of margin of error can be used in order to determine the sample size. The formula of margin of error is given by:

[tex]\rm ME =\dfrac{ Z_{\frac{\alpha }{2}}\times \sigma}{\sqrt{n} }[/tex]      ----- (1)

[tex]\rm Z_{\frac{0.1}{2}}=Z_{0.05} = 1.96[/tex]

Now, substitute the known terms in the equation (1).

[tex]\rm 1 =\dfrac{ 1.96\times2.5}{\sqrt{n} }[/tex]

Cross multiply in the above expression.

[tex]\rm \sqrt{n} = 1.96 \times 2.5[/tex]

[tex]\rm \sqrt{n} = 4.9[/tex]

n = 24.01

n [tex]\approx[/tex] 24

So, the total number of male students is 24.

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https://brainly.com/question/2096984