Some of the steps in the derivation of the quadratic formula are shown.

Step 3: –c + StartFraction b squared Over 4 a EndFraction = a(x squared + StartFraction b Over a EndFraction x + StartFraction b squared Over 4 a squared EndFraction)

Step 4a: –c + StartFraction b squared Over 4 a EndFraction = a(x + StartFraction b Over 2 a EndFraction) squared

Step 4b: negative StartFraction 4 a c Over 4 a EndFraction + StartFraction b squared Over 4 a EndFraction = a(x + StartFraction b Over 2 a EndFraction) squared

Which best explains or justifies Step 4b?

factoring a polynomial
multiplication property of equality
converting to a common denominator
addition property of equality

Respuesta :

Answer: C

Step-by-step explanation:

Took the test.

Step 4b is used in the derivation of the quadratic formula and is justified by converting to a common denominator.

The quadratic equation

An equation is regarded as quadratic if it has the general form ax^2 + bx +c =0. It is in-fact a polynomial of the second degree. One of the methods of solving a quadratic equation is by the use of the formula method.

The step that is described in step 4b as shown in the question is a key step in the derivation of the quadratic formula and it has to do with converting to a common denominator.

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