Answer:
Originally Answered: You have three light bulbs. ... A parallel circuit means that the current flows through all the loads (light bulbs in this question). Since the current is connected to each of them, disconnecting (unscrewing) one of them will still allow the current to flow to the other two and they will remain lit.
When three light bulbs will be connected in parallel by unscrewing one light bulb the other two bulbs will not stop lighting.
When three light bulbs will be connected in parallel by unscrewing one light bulb the other bulbs will not stop lighting.
Because the voltage will be same for all three bulbs by unscrewing one light bulb voltage across this particular bulb will be zero but on other bulbs remains constant so other bulbs will keep lighting.
We can understand this concept by learning relationship between the current and resistors in parallel.
If we have three bulbs then they will have resistances R1, R2, R3
since voltage remains constant so Equation will be
[tex]I=I_{1 } +I_{2} +I_{3}[/tex]
[tex]\dfrac{V}{R} =\dfrac{V}{R_{1} } +\dfrac{V}{R_{2} } +\dfrac{V}{R_{3} }[/tex]
[tex]\dfrac{1}{R} } =\dfrac{1}{R_{1} } +\dfrac{1}{R_{2} } +\dfrac{1}{R_{3} }[/tex]
This is the expression for the resistance of the bulbs if the are connected in parallel
Hence when three light bulbs will be connected in parallel by unscrewing one light bulb the other bulbs will not stop lighting
https://brainly.com/question/10703069
