Respuesta :

Answer:

Your answer is c

Step-by-step explanation:

First add two to both sides of equation:

-3x -2 + 2 ≤ - 2x + 11 + 2

Then simplify,

-3x ≤ -2x + 13

Then add 2x to both sides :

-3x + 2x ≤ - 2x + 13 + 2x

Simplify again,

-x ≤ 13

Reverse the inquality:

X ≥ - 13

Then graph it which I can't do right now but your answer will turn out to be c.

Hope this help, and have a good day! :)

(Brainliest would be appreciated)?

devishri1977

Answer:

C

Step-by-step explanation:

[tex]-\frac{1}{4}(12x+8)\leq -2x+11\\\\-\frac{1}{4}*12x+\frac{-1}{4}*8)\leq -2x+11\\\\-3x-2\leq -2x+11[/tex]

Add 3x to both sides

-2 ≤ -2x + 11 + 3x

-2 ≤ x + 11

Subtract 11 from both sides

-2-11 ≤ x + 11 -11

-13 ≤ x

X should be greater than or equal to -13

x ={-13, -12 , -11 , -10,..........}