Answer: If the other two frequencies are F and F1 then;
F-364=2
F=364+2
F=366Hz
364-F1=2
F1=364-2
F1=362Hz
Hence the two possible frequencies are 362Hz and 366Hz
Explanation:
Two tuning forks struck simultaneously produce a beat. The two possible frequencies of the other tuning fork are 366 Hz and 368 Hz.
Beat frequency is the difference between the frequencies of the two tones interacting with each other.
Given is the beat frequency of 2 Hz and the frequency of one fork is 364 Hz.
The frequency of other tuning fork will be
f2 -f1 = 2 Hz
f2 = 2 +364
f2 = 366 Hz
The other one is 366 +2 Hz = 368 Hz.
Therefore, the two possible frequencies of the other tuning fork are 366 Hz and 368 Hz.
Learn more about beat frequency.
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