Answer:
[tex]-\dfrac{1}{25}[/tex]
Step-by-step explanation:
Given the rhombus CDEF, sides FC and CD are adjacent sides.
Using coordinate geometry, to proof that a quadrilateral is a square, with regards to the slope, the slope of adjacent segments must be negative reciprocals.
In fact, by definition: Two lines with slopes [tex]m_1$ and m_2[/tex] are perpendicular if:
[tex]m_1=-\dfrac{1}{m_2}[/tex]
Therefore if :
For the rhombus to be a square:
Slope of CD [tex]=-\dfrac{1}{25}[/tex]
