We are required to determine the the value of f, rounded to the nearest hundredth
The value of f, rounded to the nearest hundredth is 0.39
Given function:
[tex]d(v) = \frac{2.15 {v}^{2} }{64.4f} [/tex]
Where,
d = stopping distance in feet
v = initial velocity in miles per hour
f = a constant related to friction
When
v = 40 mph
d = 138 ft
f = ?
[tex]d(v) = \frac{2.15 {v}^{2} }{64.4f} [/tex]
[tex]138= \frac{2.15 {(40)}^{2} }{64.4f} [/tex]
138(64.4f) = 2.15(1600)
8,887.2f = 3440
f = 3440 / 8,887.2
f = 0.3870735439733
Approximately to the nearest hundredth f = 0.39
Therefore, the value of f, rounded to the nearest hundredth is 0.39
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