A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump. Assuming normal atmospheric pressure outside the can, find the total force (in lb) on one of the 5-by-19 in. sides. (Enter the magnitude.)

Respuesta :

Answer:

The force is  [tex]F = 1397 lb[/tex]

Explanation:

From the question we are told that

    The length of the box is  [tex]l = 19 \ in[/tex]

    The width of the box is  [tex]w = 5 \ in[/tex]

     The height is  [tex]h = 4\ in[/tex]

The pressure experience on one of the sides is mathematically represented as

     [tex]p = \frac{F}{A}[/tex]

Where A is the area of the box which is mathematically evaluated as

    [tex]A = l * w[/tex]

substituting values

     [tex]A = 5 *19[/tex]

      [tex]A = 95 \ in^2[/tex]

This pressure is equivalent to the atmospheric pressure which has a constant value of  [tex]p = 14.7 pi[/tex]

This implies that

        [tex]14.7 = \frac{F}{95}[/tex]

=>   [tex]F = 14.7 *95[/tex]

=>    [tex]F = 1397 lb[/tex]