Answer:
10Ω
Explanation:
The 10Ω resistors are in series, so their combined resistance is:
10Ω + 10Ω = 20Ω
The 8Ω resistors are in parallel, so their combined resistance is:
(1/8Ω + 1/8Ω)⁻¹ = 4Ω
This 4Ω resistance is in series with the 16Ω resistor, so the combined is resistance is:
4Ω + 16Ω = 20Ω
Finally, this 20Ω resistance and the first 20Ω resistance are in parallel, so the total equivalent resistance is:
(1/20Ω + 1/20Ω)⁻¹ = 10Ω
